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顺时针打印矩阵
阅读量:338 次
发布时间:2019-03-03

本文共 1184 字,大约阅读时间需要 3 分钟。

在这里插入图片描述

难度竟然是简单,我错了好几次。。。。。。

# -*- coding:utf-8 -*-class Solution:    # matrix类型为二维列表,需要返回列表    def printMatrix(self, matrix):        # write code here        res = []        if len(matrix) == 0:            return res        top = 0        bottom = len(matrix) - 1        left = 0        right = len(matrix[0]) - 1        while True:            for i in range(left, right + 1):                res.append(matrix[top][i])            top  = top + 1            if top > bottom: break;            for i in range(top, bottom +1):                res.append(matrix[i][right])            right = right - 1            if right < left: break;            for i in range(right, left-1, -1):                res.append(matrix[bottom][i])            bottom = bottom - 1            if bottom < top: break;            for i in range(bottom, top-1, -1):                res.append(matrix[i][left])            left = left + 1            if left > right: break;                    return res

**

奇淫技巧

**

class Solution:    def spiralOrder(self, matrix: List[List[int]]) -> List[int]:        res = []        while matrix:            res += matrix.pop(0)            matrix = list(zip(*matrix))[::-1]        return res

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